Astaamaha dhererka saddexagalka saxda ah

Daabacaaddan, waxaanu tixgelin doonaa sifooyinka ugu muhiimsan ee dhererka saddexagalka saxda ah, iyo sidoo kale falanqaynta tusaalooyinka xallinta dhibaatooyinka mawduucan.

Fiiro gaar ah: saddexagalka ayaa loo yaqaan afar geesle ah, haddii mid ka mid ah xaglaha uu qumman yahay (la mid yahay 90 °) iyo labada kale ay yihiin ba'an (<90°).

Guryaha dhaadheer ee saddexagalka saxda ah

Hanti 1

Saddex-xagalka saxda ahi waxa uu leeyahay laba dherer (h₁ и h₂) lugihiisa ku beegan.

dhererka saddexaad (h₃) hoos ugu soo dhaadhaco xagal qumman.

Hanti 2

Barta isgoysyada sare ee saddexagalka midig ayaa ku taal cidhifka xagasha midig.

Hanti 3

Dhererka saddexagalka saxda ah ee lagu sawiray hypotenuse wuxuu u qaybiyaa laba saddexagal oo sax ah oo isku mid ah, kuwaas oo sidoo kale la mid ah kii asalka ahaa.

1. △US ~ △ABC laba xagal oo siman: ∠ADB = ∠LAC (xariiq toosan), ∠US = ∠ABC

2. △ADC ~ △ABC laba xagal oo siman: ∠ADC = ∠LAC (xariiq toosan), ∠ACD = ∠ACB

3. △US ~ △ADC laba xagal oo siman: ∠US = ∠DAC, ∠xUN = ∠ACD.

Cadayn: ∠xUN = 90 ° - ∠ABD (ABC). Isla markaana ∠ACD (ACB) = 90 ° - ∠ABC.

Sidaa darteed, ∠xUN = ∠ACD.

Waxaa lagu caddayn karaa si la mid ah in ∠US = ∠DAC.

Hanti 4

Saddexagalka saxda ah, dhererka loo sawiray hypotenuse waxaa loo xisaabiyaa sida soo socota:

1. Iyadoo loo marayo qaybo ka mid ah hypotenuse, oo loo sameeyay natiijada qaybinteeda iyadoo la raacayo saldhigga dhererka:

2. Iyadoo loo marayo dhererka dhinacyada saddexagalka:

Qaaciddadaan waxaa laga soo qaatay Guryaha seeraha xagasha ba'an saddexagalka saxda ah (dhinaca xagasha waxay la mid tahay saamiga lugta ka soo horjeeda iyo hypotenuse):

Fiiro gaar ah: saddexagalka saxda ah, sifooyinka dhererka guud ee lagu soo bandhigay daabacaaddayada - sidoo kale ku dabaq.

Tusaale dhibaato

Hawsha 1

Hoos-u-dhaca saddex-xagalka saxda ah waxa loo qaybiyaa dhererka loo sawiray qaybo 5 iyo 13 cm ah. Soo hel dhererka dhererkan.

Solution

Aynu isticmaalno qaacidada kowaad ee lagu soo bandhigay Hanti 4:

Hawsha 2

Lugaha saddexagalka midig waa 9 iyo 12 cm. Soo hel dhererka sare ee lagu sawiray hypotenuse.

Solution

Marka hore, aynu helno dhererka hypotenuse-ka oo weheliya ( lugaha saddexagalka ha ahaado "ku" и "B", iyo hypotenuse waa " vs"):

c² =A² + b² = 9² + 12² = 225.

Sidaas awgeed, ayaa с = 15cm.

Hadda waxaan ka codsan karnaa caanaha labaad Guryaha 4kor looga hadlay: